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3x^2+4=-x
We move all terms to the left:
3x^2+4-(-x)=0
We add all the numbers together, and all the variables
3x^2-(-1x)+4=0
We get rid of parentheses
3x^2+1x+4=0
We add all the numbers together, and all the variables
3x^2+x+4=0
a = 3; b = 1; c = +4;
Δ = b2-4ac
Δ = 12-4·3·4
Δ = -47
Delta is less than zero, so there is no solution for the equation
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